Percentage Composition Practice Questions with Answers

Concept Explanation

Percentage composition is the ratio of the mass of each element to the total mass of the compound, expressed as a percentage. This calculation allows chemists to specify the exact makeup of a chemical substance by weight, which is essential for determining empirical formulas and verifying the purity of samples. To calculate the percentage composition, you divide the total mass of a specific element in one mole of the compound by the molar mass of the entire compound and multiply by 100.

The mathematical formula is expressed as:

% Composition = (Mass of Element in 1 mole / Molar Mass of Compound) × 100%

Understanding this concept is a foundational step in mastering the mole concept. It relies heavily on the Law of Definite Proportions, which states that a given chemical compound always contains its component elements in a fixed ratio by mass. For instance, pure water (H₂O) will always consist of approximately 11.2% hydrogen and 88.8% oxygen by mass, regardless of the source. This consistency is why percentage composition is a reliable tool in analytical chemistry.

To perform these calculations accurately, you must use the average atomic masses found on the Periodic Table of Elements. Often, percentage composition problems serve as a bridge to more complex topics like mass-to-mass stoichiometry, where knowing the mass distribution within a molecule is necessary for predicting reaction yields.

Solved Examples

Below are step-by-step solutions for calculating the percentage composition of various compounds.

1. Calculate the percentage composition of Sodium (Na) and Chlorine (Cl) in Sodium Chloride (NaCl).

   1. Find the molar mass of NaCl: Na (22.99 g/mol) + Cl (35.45 g/mol) = 58.44 g/mol.

   2. Calculate % Na: (22.99 / 58.44) × 100 = 39.34%.

   3. Calculate % Cl: (35.45 / 58.44) × 100 = 60.66%.

   4. Check: 39.34% + 60.66% = 100%.

2. Determine the percentage of Oxygen in Sulfuric Acid (H₂SO₄).

   1. Calculate the total molar mass: (2 × 1.01) + 32.06 + (4 × 16.00) = 2.02 + 32.06 + 64.00 = 98.08 g/mol.

   2. Identify the mass of oxygen: 4 atoms × 16.00 g/mol = 64.00 g.

   3. Apply the formula: (64.00 / 98.08) × 100 = 65.25%.

3. Calculate the percent composition of all elements in Glucose (C₆H₁₂O₆).

   1. Molar mass: (6 × 12.01) + (12 × 1.01) + (6 × 16.00) = 72.06 + 12.12 + 96.00 = 180.18 g/mol.

   2. % Carbon: (72.06 / 180.18) × 100 = 39.99%.

   3. % Hydrogen: (12.12 / 180.18) × 100 = 6.73%.

   4. % Oxygen: (96.00 / 180.18) × 100 = 53.28%.

Practice Questions

1. Calculate the percentage of Nitrogen in Ammonia (NH₃).

2. A compound is found to contain 5.40g of Calcium and 9.60g of Sulfur. What is the percentage composition of Calcium in the sample?

3. Determine the percent composition of Carbon in Carbon Dioxide (CO₂).

4. Calculate the percentage by mass of water in Magnesium Sulfate Heptahydrate (MgSO₄·7H₂O).

5. Find the percentage composition of Iron in Iron(III) Oxide (Fe₂O₃).

6. Which has a higher percentage of Nitrogen: Ammonium Nitrate (NH₄NO₃) or Urea (CH₄N₂O)?

7. A 25.0g sample of an unknown metal oxide contains 17.5g of the metal. What is the percentage of oxygen in the compound?

8. Calculate the percentage of Phosphorus in Phosphoric Acid (H₃PO₄).

9. Determine the percent composition of all elements in Calcium Carbonate (CaCO₃).

10. If a fertilizer is labeled 20-10-10, it contains 20% Nitrogen. How many grams of Nitrogen are in a 50kg bag?

Answers & Explanations

1. 82.25% Nitrogen. Molar mass of NH₃ = 14.01 + (3 × 1.01) = 17.04 g/mol. % N = (14.01 / 17.04) × 100 = 82.22%.

2. 36.00% Calcium. Total mass = 5.40g + 9.60g = 15.00g. % Ca = (5.40 / 15.00) × 100 = 36.00%.

3. 27.29% Carbon. Molar mass of CO₂ = 12.01 + (2 × 16.00) = 44.01 g/mol. % C = (12.01 / 44.01) × 100 = 27.29%.

4. 51.17% Water. Mass of 7H₂O = 7 × 18.02 = 126.14. Molar mass of MgSO₄·7H₂O = 24.31 + 32.06 + (4 × 16.00) + 126.14 = 246.51 g/mol. % H₂O = (126.14 / 246.51) × 100 = 51.17%.

5. 69.94% Iron. Molar mass of Fe₂O₃ = (2 × 55.85) + (3 × 16.00) = 111.70 + 48.00 = 159.70 g/mol. % Fe = (111.70 / 159.70) × 100 = 69.94%.

6. Urea (46.65%). NH₄NO₃ molar mass = 80.06 g/mol; % N = 28.02/80.06 = 35.00%. Urea molar mass = 60.07 g/mol; % N = 28.02/60.07 = 46.65%. Urea is higher.

7. 30.00% Oxygen. Mass of Oxygen = Total mass - Mass of Metal = 25.0g - 17.5g = 7.5g. % O = (7.5 / 25.0) × 100 = 30.00%.

8. 31.61% Phosphorus. Molar mass of H₃PO₄ = (3 × 1.01) + 30.97 + (4 × 16.00) = 98.00 g/mol. % P = (30.97 / 98.00) × 100 = 31.60%.

9. Ca: 40.04%, C: 12.00%, O: 47.96%. Molar mass = 40.08 + 12.01 + (3 × 16.00) = 100.09 g/mol. % Ca = 40.08/100.09; % C = 12.01/100.09; % O = 48.00/100.09.

10. 10kg. 20% of 50kg = 0.20 × 50 = 10kg.

Quick Quiz

Frequently Asked Questions

What is the difference between percentage composition and empirical formula?

Percentage composition provides the mass percent of each element, while the empirical formula gives the simplest whole-number ratio of atoms in the compound. You can use the percentage composition to derive the empirical formula by assuming a 100g sample and converting those masses to moles.

Can the percentage composition of a compound change?

No, the percentage composition of a pure chemical compound is constant regardless of the sample size or source. This is a fundamental principle of chemistry known as the Law of Constant Composition or Definite Proportions.

How do hydrates affect percentage composition calculations?

When calculating the percentage composition of a hydrate, you must include the mass of the water molecules in the total molar mass of the compound. You can calculate the percentage of the anhydrous salt or the percentage of water specifically, as seen in moles to grams conversions.

Is percentage composition the same as mass percent?

Yes, in the context of a pure chemical compound, these terms are interchangeable. Both refer to the mass of a component divided by the total mass of the mixture or compound, multiplied by 100.

Why do my percentages sometimes add up to 99.9% or 100.1%?

This minor discrepancy is usually due to rounding during the calculation steps. While the theoretical sum is always exactly 100%, using different periodic tables with varying significant figures can lead to slight rounding differences.

Does percentage composition help identify an unknown substance?

Yes, by comparing the experimentally determined percentage composition of an unknown substance to the theoretical values of known compounds, scientists can narrow down or confirm the identity of a chemical.

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