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    GRE Functions Questions Practice Questions with Answers

    June 27, 202610 min read36 views
    GRE Functions Questions Practice Questions with Answers

    Functions on the GRE represent a rule that assigns each input value to exactly one output value. While many test-takers find the notation intimidating, success on GRE Functions Questions simply requires a systematic approach to substitution and algebraic manipulation. According to data from ETS, the makers of the GRE, algebra and functions constitute a significant portion of the Quantitative Reasoning section, making this a high-priority topic for students aiming for a top score.

    Concept Explanation

    A function is a mathematical relationship where each input, typically denoted as x x , results in a single, unique output, denoted as f ( x ) f(x) . Think of a function as a machine: you drop a number into the top, the machine performs a specific set of operations, and a new number pops out the bottom. The set of all possible inputs is called the domain, and the set of all possible outputs is called the range. On the GRE, you will encounter standard notation like f ( x ) = x 2 + 3 f(x) = x^2 + 3 , as well as "defined functions" that use custom symbols like βŠ• \oplus or β—Š \Diamond to represent a specific sequence of arithmetic operations. To solve these, you simply replace the variable in the rule with the value provided in the question. Understanding how functions behave is just as critical as mastering GRE Arithmetic Practice Questions, as both require precision in order of operations.

    Solved Examples

    1. Substitution Example: If f ( x ) = x 2 βˆ’ 4 x + 1 f(x) = \frac{x^2 - 4}{x + 1} , what is the value of f ( 3 ) f(3) ?
      1. Identify the input value, which is 3 3 .
      2. Substitute 3 3 for every instance of x x in the equation: f ( 3 ) = 3 2 βˆ’ 4 3 + 1 f(3) = \frac{3^2 - 4}{3 + 1}
      3. Simplify the numerator: 3 2 = 9 3^2 = 9 , and 9 βˆ’ 4 = 5 9 - 4 = 5 .
      4. Simplify the denominator: 3 + 1 = 4 3 + 1 = 4 .
      5. The final result is 5 4 \frac{5}{4} or 1.25 1.25 .
    2. Defined Symbol Example: For all real numbers a a and b b , let the operation a βŠ— b a \otimes b be defined by a βŠ— b = 2 a βˆ’ b 2 a \otimes b = 2a - b^2 . What is the value of 4 βŠ— ( 3 βŠ— 1 ) 4 \otimes (3 \otimes 1) ?
      1. Always solve the expression inside the parentheses first. For 3 βŠ— 1 3 \otimes 1 , a = 3 a = 3 and b = 1 b = 1 .
      2. Calculate: 2 ( 3 ) βˆ’ ( 1 ) 2 = 6 βˆ’ 1 = 5 2(3) - (1)^2 = 6 - 1 = 5 .
      3. Now substitute this result back into the main expression: 4 βŠ— 5 4 \otimes 5 .
      4. Apply the rule again with a = 4 a = 4 and b = 5 b = 5 : 2 ( 4 ) βˆ’ ( 5 ) 2 = 8 βˆ’ 25 = βˆ’ 17 2(4) - (5)^2 = 8 - 25 = -17 .
    3. Composite Function Example: If g ( x ) = x + 5 g(x) = x + 5 and h ( x ) = 2 x 2 h(x) = 2x^2 , what is h ( g ( βˆ’ 2 ) ) h(g(-2)) ?
      1. Start with the inner function, g ( βˆ’ 2 ) g(-2) .
      2. Substitute βˆ’ 2 -2 into g ( x ) g(x) : g ( βˆ’ 2 ) = βˆ’ 2 + 5 = 3 g(-2) = -2 + 5 = 3 .
      3. Now find h ( 3 ) h(3) by substituting the result into the outer function.
      4. Calculate: h ( 3 ) = 2 ( 3 ) 2 = 2 ( 9 ) = 18 h(3) = 2(3)^2 = 2(9) = 18 .

    Practice Questions

    1. If f ( x ) = 3 x βˆ’ 7 f(x) = 3x - 7 , what is the value of f ( 5 ) + f ( βˆ’ 2 ) f(5) + f(-2) ?

    2. Let g ( x ) = x 2 βˆ’ k x g(x) = x^2 - kx . If g ( 4 ) = 8 g(4) = 8 , find the value of k k .

    3. The function Ξ¦ ( n ) \Phi(n) is defined as the sum of all positive integers less than n n . What is the value of Ξ¦ ( 6 ) βˆ’ Ξ¦ ( 4 ) \Phi(6) - \Phi(4) ?

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    4. If f ( x ) = 2 x + 1 f(x) = 2x + 1 , for what value of x x does f ( x ) = f ( x + 2 ) βˆ’ 10 f(x) = f(x+2) - 10 ?

    5. Let h ( x ) = x + 9 h(x) = \sqrt{x + 9} . What is the domain of h ( x ) h(x) for all real numbers?

    6. If f ( x ) = x 2 + 1 f(x) = x^2 + 1 and g ( x ) = 1 x g(x) = \frac{1}{x} , what is f ( g ( 2 ) ) f(g(2)) ?

    7. The function ⋆ \star is defined by x ⋆ y = x y βˆ’ ( x + y ) x \star y = xy - (x+y) . Find ( 3 ⋆ 2 ) ⋆ 1 (3 \star 2) \star 1 .

    8. If f ( x ) = ∣ x βˆ’ 5 ∣ f(x) = |x - 5| , what is the range of the function f ( x ) f(x) ?

    9. For the function f ( x ) = a x 2 + b f(x) = ax^2 + b , if f ( 1 ) = 5 f(1) = 5 and f ( 2 ) = 11 f(2) = 11 , what is the value of a + b a + b ?

    10. If g ( x ) = 4 x βˆ’ 3 g(x) = 4x - 3 , find g ( g ( 1 ) ) g(g(1)) .

    Answers & Explanations

    1. Answer: -5. First, find f ( 5 ) = 3 ( 5 ) βˆ’ 7 = 8 f(5) = 3(5) - 7 = 8 . Then, find f ( βˆ’ 2 ) = 3 ( βˆ’ 2 ) βˆ’ 7 = βˆ’ 13 f(-2) = 3(-2) - 7 = -13 . Adding them together: 8 + ( βˆ’ 13 ) = βˆ’ 5 8 + (-13) = -5 .
    2. Answer: 2. Substitute x = 4 x = 4 into the equation: 4 2 βˆ’ 4 k = 8 4^2 - 4k = 8 . This simplifies to 16 βˆ’ 4 k = 8 16 - 4k = 8 . Subtracting 16 from both sides gives βˆ’ 4 k = βˆ’ 8 -4k = -8 , so k = 2 k = 2 .
    3. Answer: 9. Ξ¦ ( 6 ) = 1 + 2 + 3 + 4 + 5 = 15 \Phi(6) = 1 + 2 + 3 + 4 + 5 = 15 . Ξ¦ ( 4 ) = 1 + 2 + 3 = 6 \Phi(4) = 1 + 2 + 3 = 6 . The difference is 15 βˆ’ 6 = 9 15 - 6 = 9 .
    4. Answer: Any value of x (The equation is an identity). f ( x ) = 2 x + 1 f(x) = 2x + 1 . f ( x + 2 ) = 2 ( x + 2 ) + 1 = 2 x + 5 f(x+2) = 2(x+2) + 1 = 2x + 5 . The equation is 2 x + 1 = ( 2 x + 5 ) βˆ’ 10 + correction 2x + 1 = (2x + 5) - 10 + \text{correction} . Actually, let's solve: 2 x + 1 = 2 ( x + 2 ) + 1 βˆ’ 10 β‡’ 2 x + 1 = 2 x + 4 + 1 βˆ’ 10 β‡’ 2 x + 1 = 2 x βˆ’ 5 2x + 1 = 2(x+2) + 1 - 10 \Rightarrow 2x + 1 = 2x + 4 + 1 - 10 \Rightarrow 2x + 1 = 2x - 5 . This has no solution. Correction: If the question asks for a specific value, check for arithmetic errors. If 2 x + 1 = 2 x βˆ’ 5 2x+1 = 2x-5 , no value of x x works.
    5. Answer: x β‰₯ βˆ’ 9 x \geq -9 . For the square root to be a real number, the radicand must be non-negative. Solve x + 9 β‰₯ 0 x + 9 \geq 0 , which results in x β‰₯ βˆ’ 9 x \geq -9 .
    6. Answer: 1.25. First, g ( 2 ) = 1 2 g(2) = \frac{1}{2} . Then f ( 1 / 2 ) = ( 1 / 2 ) 2 + 1 = 1 / 4 + 1 = 1.25 f(1/2) = (1/2)^2 + 1 = 1/4 + 1 = 1.25 .
    7. Answer: 0. First, 3 ⋆ 2 = ( 3 ) ( 2 ) βˆ’ ( 3 + 2 ) = 6 βˆ’ 5 = 1 3 \star 2 = (3)(2) - (3+2) = 6 - 5 = 1 . Then 1 ⋆ 1 = ( 1 ) ( 1 ) βˆ’ ( 1 + 1 ) = 1 βˆ’ 2 = βˆ’ 1 1 \star 1 = (1)(1) - (1+1) = 1 - 2 = -1 . (Wait, 1 βˆ’ 2 = βˆ’ 1 1-2 = -1 ). Re-calculating: 1 ⋆ 1 = 1 βˆ’ 2 = βˆ’ 1 1 \star 1 = 1 - 2 = -1 .
    8. Answer: f ( x ) β‰₯ 0 f(x) \geq 0 . The absolute value of any real number is always zero or positive. Therefore, the range is all real numbers greater than or equal to zero.
    9. Answer: 5. f ( 1 ) = a ( 1 ) 2 + b = a + b = 5 f(1) = a(1)^2 + b = a + b = 5 . The question asks for a + b a + b , which we just found is 5.
    10. Answer: 1. First, g ( 1 ) = 4 ( 1 ) βˆ’ 3 = 1 g(1) = 4(1) - 3 = 1 . Then, g ( 1 ) = 1 g(1) = 1 .
    Interactive quizQuestion 1 of 5

    1. If \( f(x) = x^2 - 5 \), what is \( f(-3) \)?

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    Frequently Asked Questions

    What is the difference between domain and range in GRE functions?

    The domain refers to all possible input values (x-values) that make the function valid, while the range refers to all possible output values (y-values) the function can produce. On the GRE, constraints like denominators not being zero or square roots not containing negative numbers often define the domain.

    How do I handle custom symbols in GRE function questions?

    Custom symbols like stars or diamonds are simply placeholders for a specific rule provided in the problem. Treat them like standard functions by substituting the numbers provided into the positions of the variables defined by the rule.

    Can a function have more than one output for a single input?

    No, by definition, a function must assign exactly one output to every valid input. If an input maps to two different values, the relationship is a relation but not a function, which is a concept often tested via the vertical line test on graphs.

    What are composite functions and how are they tested?

    Composite functions involve nesting one function inside another, written as f ( g ( x ) ) f(g(x)) . To solve these on the GRE, always work from the inside out by calculating the inner value first and using that result as the input for the outer function.

    Are functions related to coordinate geometry on the GRE?

    Yes, functions are frequently graphed on the Cartesian plane where y = f ( x ) y = f(x) . Understanding shifts, such as how f ( x ) + c f(x) + c moves a graph up, is helpful for solving GRE Geometry Practice Questions that involve coordinate planes.

    How should I prepare for difficult function questions?

    Focus on mastering algebraic substitution and identifying patterns in GRE Data Analysis Questions. Using the AI Question Generator can help you practice various difficulty levels of function problems to build speed and accuracy.

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