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    Medium SAT Word Problems Practice Questions

    April 26, 202610 min read24 views
    Medium SAT Word Problems Practice Questions

    Medium SAT Word Problems Practice Questions

    Mastering medium SAT word problems is a critical step for students aiming to break into the 600-800 score range on the Math section. These problems require more than just basic arithmetic; they demand the ability to translate complex English descriptions into precise algebraic equations. By practicing these intermediate-level scenarios, you develop the analytical skills needed to handle multi-step calculations and logical reasoning under timed conditions.

    Concept Explanation

    Medium SAT word problems are mathematical scenarios that require students to interpret a narrative, identify relevant variables, and apply algebraic or geometric principles to find a solution. These problems often bridge the gap between simple computation and complex modeling. To solve them effectively, you must follow a structured approach: define your variables, extract the given constants, and set up an equation or inequality that represents the relationship described in the text. According to Khan Academy's SAT prep, the most common topics include linear growth, percentages, ratios, and systems of equations.

    Success on these questions depends on identifying "key trigger words." For example, "is" usually translates to an equals sign = = , "per" implies a rate or multiplication, and "at most" indicates a less-than-or-equal-to sign ≀ \leq . If you find yourself struggling with the foundations of these setups, reviewing Medium SAT Algebra Practice Questions can provide the necessary background in equation manipulation.

    Solved Examples

    1. Example 1: Linear Modeling
      A car rental agency charges a flat fee of $35.00 plus $0.15 per mile driven. If a customer was charged $62.75 for a one-day rental, how many miles did they drive?
      Solution:
      1. Define the variable: Let m m be the number of miles driven.
      2. Set up the equation: The total cost is the flat fee plus the mileage rate, so 35 + 0.15 m = 62.75 35 + 0.15m = 62.75 .
      3. Subtract 35 from both sides: 0.15 m = 27.75 0.15m = 27.75 .
      4. Divide by 0.15: m = 27.75 0.15 = 185 m = \frac{27.75}{0.15} = 185 .
      5. The customer drove 185 miles.
    2. Example 2: Percentages and Totals
      A laptop originally priced at $800 is on sale for 20% off. After the discount, an 8% sales tax is applied to the sale price. What is the final cost of the laptop?
      Solution:
      1. Calculate the sale price: 800 Γ— ( 1 βˆ’ 0.20 ) = 800 Γ— 0.80 = 640 800 \times (1 - 0.20) = 800 \times 0.80 = 640 .
      2. Apply the sales tax to the $640: 640 Γ— ( 1 + 0.08 ) = 640 Γ— 1.08 640 \times (1 + 0.08) = 640 \times 1.08 .
      3. Multiply: 640 Γ— 1.08 = 691.20 640 \times 1.08 = 691.20 .
      4. The final cost is $691.20.
    3. Example 3: Systems of Equations
      A movie theater sells adult tickets for $12 each and child tickets for $8 each. On a Saturday, the theater sold 150 tickets total and collected $1,560. How many adult tickets were sold?
      Solution:
      1. Define variables: Let a a be adult tickets and c c be child tickets.
      2. Create equations: a + c = 150 a + c = 150 and 12 a + 8 c = 1560 12a + 8c = 1560 .
      3. Solve for c c in the first equation: c = 150 βˆ’ a c = 150 - a .
      4. Substitute into the second equation: 12 a + 8 ( 150 βˆ’ a ) = 1560 12a + 8(150 - a) = 1560 .
      5. Distribute: 12 a + 1200 βˆ’ 8 a = 1560 12a + 1200 - 8a = 1560 .
      6. Combine like terms: 4 a + 1200 = 1560 4a + 1200 = 1560 .
      7. Subtract 1200: 4 a = 360 4a = 360 .
      8. Divide by 4: a = 90 a = 90 . There were 90 adult tickets sold.

    Practice Questions

    1. A technician charges a one-time service fee of $50 plus an hourly rate of $30. If a total bill for a repair was $185, how many hours did the technician work?

    2. A rectangular garden has a perimeter of 64 feet. The length of the garden is 4 feet longer than the width. What is the area of the garden in square feet?

    3. In a certain high school, the ratio of sophomores to juniors is 5:4. If there are 320 juniors, how many sophomores are there?

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    4. A bakery sells bagels for $1.50 each and muffins for $2.25 each. If a customer buys a total of 12 items and spends exactly $21.00, how many muffins did they buy?

    5. An investment account grows at a rate of 5% compound interest annually. If the initial deposit was $2,000, which of the following expressions represents the value of the account after t t years?
    A) 2000 ( 0.05 ) t 2000(0.05)^t
    B) 2000 ( 1.05 ) t 2000(1.05)^t
    C) 2000 + 0.05 t 2000 + 0.05t
    D) 2000 + 1.05 t 2000 + 1.05t

    6. A water tank currently holds 400 gallons of water. Water is being pumped out of the tank at a constant rate of 15 gallons per minute. After how many minutes will the tank contain exactly 145 gallons?

    7. A local gym offers two membership plans. Plan A costs $10 per month plus $5 per visit. Plan B costs $40 per month for unlimited visits. What is the minimum number of visits per month for which Plan B is cheaper than Plan A?

    8. The sum of three consecutive integers is 72. What is the value of the largest integer?

    9. A recipe calls for 3 cups of flour to make 24 cookies. How many cups of flour are needed to make 60 cookies?

    10. A store owner buys a jacket for $40 and marks up the price by 60%. During a clearance sale, the jacket is discounted by 25% off the marked-up price. What is the final sale price of the jacket?

    Answers & Explanations

    1. Answer: 4.5 hours. Set up the equation 50 + 30 h = 185 50 + 30h = 185 . Subtract 50 to get 30 h = 135 30h = 135 . Divide by 30 to get h = 4.5 h = 4.5 .
    2. Answer: 252 sq ft. Let width be w w and length be w + 4 w+4 . Perimeter 2 ( w + w + 4 ) = 64 2(w + w + 4) = 64 , so 4 w + 8 = 64 4w + 8 = 64 , giving w = 14 w = 14 . Length is 18. Area is 14 Γ— 18 = 252 14 \times 18 = 252 .
    3. Answer: 400 sophomores. Set up the proportion 5 4 = s 320 \frac{5}{4} = \frac{s}{320} . Cross-multiply: 4 s = 1600 4s = 1600 . Divide by 4 to find s = 400 s = 400 .
    4. Answer: 4 muffins. Let b b be bagels and m m be muffins. b + m = 12 b + m = 12 and 1.5 b + 2.25 m = 21 1.5b + 2.25m = 21 . Substitute b = 12 βˆ’ m b = 12 - m into the second equation: 1.5 ( 12 βˆ’ m ) + 2.25 m = 21 1.5(12 - m) + 2.25m = 21 . This simplifies to 18 βˆ’ 1.5 m + 2.25 m = 21 18 - 1.5m + 2.25m = 21 , then 0.75 m = 3 0.75m = 3 , so m = 4 m = 4 .
    5. Answer: B. The standard formula for exponential growth is P ( 1 + r ) t P(1 + r)^t . Here P = 2000 P = 2000 and r = 0.05 r = 0.05 , so the expression is 2000 ( 1.05 ) t 2000(1.05)^t .
    6. Answer: 17 minutes. Use the equation 400 βˆ’ 15 m = 145 400 - 15m = 145 . Subtract 400 from both sides: βˆ’ 15 m = βˆ’ 255 -15m = -255 . Divide by -15: m = 17 m = 17 .
    7. Answer: 7 visits. We want to find when 40 < 10 + 5 v 40 < 10 + 5v . Subtract 10: 30 < 5 v 30 < 5v . Divide by 5: 6 < v 6 < v . The first whole number greater than 6 is 7.
    8. Answer: 25. Let the integers be n , n + 1 , n + 2 n, n+1, n+2 . Their sum is 3 n + 3 = 72 3n + 3 = 72 . Subtract 3: 3 n = 69 3n = 69 . Divide by 3: n = 23 n = 23 . The largest is 23 + 2 = 25 23 + 2 = 25 .
    9. Answer: 7.5 cups. Set up the ratio 3 24 = x 60 \frac{3}{24} = \frac{x}{60} . Cross-multiply: 180 = 24 x 180 = 24x . Divide by 24: x = 7.5 x = 7.5 .
    10. Answer: $48. Markup: 40 Γ— 1.6 = 64 40 \times 1.6 = 64 . Discount: 64 Γ— 0.75 = 48 64 \times 0.75 = 48 .

    Quick Quiz

    Interactive Quiz 5 questions

    1. A photographer charges $100 for a session plus $15 per edited photo. If a client spends $220, how many edited photos did they receive?

    • A 6
    • B 8
    • C 10
    • D 12
    Check answer

    Answer: B. 8

    2. If the ratio of red marbles to blue marbles in a jar is 3:7 and there are 42 blue marbles, how many red marbles are in the jar?

    • A 14
    • B 18
    • C 21
    • D 28
    Check answer

    Answer: B. 18

    3. A car travels at a constant speed of 65 miles per hour. Which equation represents the distance d d traveled in h h hours?

    • A d = 65 h d = 65h
    • B h = 65 d h = 65d
    • C d = 65 + h d = 65 + h
    • D d = 65 h d = \frac{65}{h}
    Check answer

    Answer: A. d = 65 h d = 65h

    4. A jacket is on sale for 30% off its original price of $120. What is the sale price?

    • A $36
    • B $90
    • C $84
    • D $70
    Check answer

    Answer: C. $84

    5. The sum of two numbers is 20 and their difference is 4. What is the larger number?

    • A 10
    • B 12
    • C 14
    • D 16
    Check answer

    Answer: B. 12

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    Frequently Asked Questions

    What makes an SAT word problem "medium" difficulty?

    Medium difficulty problems usually involve two or three steps or require you to set up a system of equations rather than a single simple equation. They often include distracting information or require unit conversions that easy problems do not.

    How do I translate "at least" and "at most" into math?

    "At least" means that a value can be equal to or greater than a number, represented by the β‰₯ \geq symbol. "At most" means the value can be equal to or less than a number, represented by the ≀ \leq symbol.

    Should I use a calculator for all medium word problems?

    While a calculator is permitted on the Math section, it is often faster to solve medium problems by hand if the numbers are simple. Use the calculator for complex decimals or large divisions to avoid manual calculation errors.

    How can I improve my speed on SAT word problems?

    The best way to improve speed is through consistent practice and learning to identify common problem patterns, such as rate-time-distance or percent change. For more targeted practice, explore our Medium SAT Math Practice Questions.

    What is the most common mistake on SAT word problems?

    The most common mistake is solving for the wrong variable, such as finding x x when the question asks for x + 5 x + 5 . Always re-read the final sentence of the prompt before selecting your answer to ensure you are answering the specific question asked.

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