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    Medium ACT Statistics Practice Questions

    June 7, 202611 min read65 views
    Medium ACT Statistics Practice Questions

    Mastering medium ACT statistics practice questions is essential for students aiming to score in the 25–30 range on the math section. Statistics on the ACT goes beyond simple averages; it requires a deep understanding of how data sets change when numbers are added, how weighted averages function, and the relationship between mean, median, and mode in various contexts.

    To perform well, you must be comfortable with data interpretation and the logical application of statistical formulas. For a broader look at the math section, you can explore ACT Math Practice Questions with Answers to see how statistics fits into the overall exam structure. This guide will provide the rigorous practice needed to handle the multi-step statistics problems that frequently appear in the middle of the test.

    Concept Explanation

    ACT statistics focuses on the measures of central tendency (mean, median, and mode) and measures of spread (range and standard deviation) within a set of data. The mean is the arithmetic average, calculated by dividing the sum of all terms by the number of terms. The median is the middle value when the data is ordered from least to greatest. If there is an even number of terms, the median is the average of the two middle terms. The mode is the value that appears most frequently. On medium-level questions, the ACT often tests how these values shift when a new data point is introduced or when a set is modified.

    Another critical concept is the weighted average, where different groups contribute differently to the final mean based on their size. For example, if one class of 20 students has a certain average and another class of 30 students has a different average, you cannot simply average the two means; you must account for the total number of students. Understanding these nuances is a core part of comprehensive ACT Prep.

    For more specific practice on logic-based math, check out ACT Word Problems Practice Questions with Answers, as many statistics questions are presented as narratives. You can also utilize an AI Question Generator to create additional sets of data for practice.

    Solved Examples

    These examples demonstrate how to approach multi-step statistics problems logically.

    Example 1: Finding a Missing Value
    A student has taken 4 tests and has an average score of 85. What score must the student earn on the 5th test to raise their overall average to 88?

    1. Calculate the current total points: 4 Γ— 85 = 340 4 \times 85 = 340 .

    2. Calculate the required total points for 5 tests: 5 Γ— 88 = 440 5 \times 88 = 440 .

    3. Subtract the current total from the required total: 440 βˆ’ 340 = 100 440 - 340 = 100 .

    4. The student must score 100 on the 5th test.

    Example 2: Weighted Average
    In a certain class, 10 students scored an average of 90 on a quiz, and 15 students scored an average of 80. What is the average score for the entire class of 25 students?

    1. Find the total points for the first group: 10 Γ— 90 = 900 10 \times 90 = 900 .

    2. Find the total points for the second group: 15 Γ— 80 = 1 , 200 15 \times 80 = 1,200 .

    3. Add the totals together: 900 + 1 , 200 = 2 , 100 900 + 1,200 = 2,100 .

    4. Divide by the total number of students: 2 , 100 25 = 84 \frac{2,100}{25} = 84 .

    Example 3: Median with Frequency Tables
    A survey asked 10 people how many pets they own. The results were: 0, 0, 1, 1, 1, 2, 2, 3, 4, 5. What is the median number of pets?

    1. The data is already ordered: 0, 0, 1, 1, 1, 2, 2, 3, 4, 5.

    2. Since there are 10 values (an even number), the median is the average of the 5th and 6th values.

    3. The 5th value is 1 and the 6th value is 2.

    4. Calculate the average: 1 + 2 2 = 1.5 \frac{1 + 2}{2} = 1.5 .

    Practice Questions

    Test your skills with these medium ACT statistics practice questions. These are similar in difficulty to questions 30–50 on a typical ACT math section.

    1. The average of five consecutive integers is 12. What is the value of the largest integer in this set?

    2. A set of 7 numbers has a mean of 14. If two numbers, 18 and 22, are removed from the set, what is the mean of the remaining 5 numbers?

    3. In a data set of 12 numbers, the mean is 20 and the median is 18. If every number in the set is increased by 5, what are the new mean and median?

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    4. A basketball team scored an average of 62 points per game over their first 10 games. If they score 80 points in their 11th game, what is their new average score per game? (Round to the nearest tenth).

    5. A data set consists of the numbers {4, 8, 12, 16, 20}. If a new number, x x , is added to the set, the new mean becomes 13. What is the value of x x ?

    6. The weights of five boxes are 12, 15, 18, 20, and 25 pounds. If a sixth box weighing 30 pounds is added, how much does the median weight increase?

    7. A teacher calculates the mean grade for a class of 20 students to be 78. She later discovers that one student's grade was recorded as 60 instead of 80. What is the correct mean for the class?

    8. For a set of 5 positive integers, the mean is 10, the median is 10, and the mode is 12. What is the smallest possible value that could be in this set?

    9. A set of data contains 10 values. If the sum of the values is 150, and the range is 20, what is the mean of the set?

    10. If the average of a , b , a, b, and c c is 15, and the average of a , b , c , d , a, b, c, d, and e e is 20, what is the average of d d and e e ?

    Answers & Explanations

    1. Answer: 14. Let the integers be n βˆ’ 2 , n βˆ’ 1 , n , n + 1 , n + 2 n-2, n-1, n, n+1, n+2 . The average of consecutive integers is always the middle value. Thus, n = 12 n = 12 . The largest integer is n + 2 = 14 n+2 = 14 .

    2. Answer: 11.6. The original sum is 7 Γ— 14 = 98 7 \times 14 = 98 . Subtract the removed numbers: 98 βˆ’ ( 18 + 22 ) = 58 98 - (18 + 22) = 58 . The new mean is 58 / 5 = 11.6 58 / 5 = 11.6 .

    3. Answer: Mean 25, Median 23. When a constant is added to every value in a set, the mean and median both increase by that same constant. 20 + 5 = 25 20 + 5 = 25 and 18 + 5 = 23 18 + 5 = 23 . For more on number shifts, see ACT Number Properties Practice Questions.

    4. Answer: 63.6. Original total points: 10 Γ— 62 = 620 10 \times 62 = 620 . New total: 620 + 80 = 700 620 + 80 = 700 . New average: 700 / 11 β‰ˆ 63.636 700 / 11 \approx 63.636 , which rounds to 63.6.

    5. Answer: 18. The sum of the first five numbers is 4 + 8 + 12 + 16 + 20 = 60 4 + 8 + 12 + 16 + 20 = 60 . For 6 numbers to have a mean of 13, the sum must be 6 Γ— 13 = 78 6 \times 13 = 78 . Thus, x = 78 βˆ’ 60 = 18 x = 78 - 60 = 18 .

    6. Answer: 1 pound. The original median of {12, 15, 18, 20, 25} is 18. The new set is {12, 15, 18, 20, 25, 30}. The new median is the average of the 3rd and 4th terms: ( 18 + 20 ) / 2 = 19 (18 + 20) / 2 = 19 . The increase is 19 βˆ’ 18 = 1 19 - 18 = 1 .

    7. Answer: 79. The initial sum was 20 Γ— 78 = 1 , 560 20 \times 78 = 1,560 . The difference in the error is 80 βˆ’ 60 = 20 80 - 60 = 20 . The correct sum is 1 , 560 + 20 = 1 , 580 1,560 + 20 = 1,580 . The correct mean is 1 , 580 / 20 = 79 1,580 / 20 = 79 .

    8. Answer: 4. The sum of the 5 integers is 5 Γ— 10 = 50 5 \times 10 = 50 . Since the mode is 12 and the median is 10, the set looks like {x, y, 10, 12, 12}. To minimize x x , we maximize y y . Since y y must be less than or equal to the median (10), let y = 10 y = 10 . Sum: x + 10 + 10 + 12 + 12 = 50 β†’ x + 44 = 50 β†’ x = 6 x + 10 + 10 + 12 + 12 = 50 \rightarrow x + 44 = 50 \rightarrow x = 6 . Wait, if y = 6 y = 6 , then x x could be smaller? Let's check: {x, 10, 10, 12, 12}. Sum is x + 44 = 50 β†’ x = 6 x + 44 = 50 \rightarrow x = 6 . If we use {4, 10, 10, 12, 12}, the sum is 48 (too low). The smallest possible value is 6.

    9. Answer: 15. Mean is simply total sum divided by the number of values. 150 / 10 = 15 150 / 10 = 15 . The range is irrelevant information here.

    10. Answer: 27.5. Sum of a , b , c = 3 Γ— 15 = 45 a, b, c = 3 \times 15 = 45 . Sum of a , b , c , d , e = 5 Γ— 20 = 100 a, b, c, d, e = 5 \times 20 = 100 . Therefore, d + e = 100 βˆ’ 45 = 55 d + e = 100 - 45 = 55 . The average of d d and e e is 55 / 2 = 27.5 55 / 2 = 27.5 .

    Interactive quizQuestion 1 of 5

    1. If the mean of a set of 6 numbers is 12, what is the sum of the numbers?

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    Frequently Asked Questions

    How does the ACT test standard deviation?

    The ACT rarely asks you to calculate standard deviation using the complex formula found on Wikipedia. Instead, it tests your conceptual understanding of spread; for instance, knowing that a set with values spread far apart has a higher standard deviation than a set with values clustered near the mean.

    What is the difference between mean and median on the ACT?

    The mean is the calculated average, while the median is the physical middle of the data. The ACT often asks which value is more affected by an "outlier," or a number much larger or smaller than the rest of the set, which is always the mean.

    How do I handle weighted averages?

    To solve weighted averages, multiply each value by its corresponding weight (or count), sum those products, and divide by the total number of items. This is a common feature in problems involving different class sizes or mixed percentages, similar to concepts in ACT Percentage Practice Questions.

    Can I use a calculator for statistics questions?

    Yes, the ACT allows calculators, and many have built-in statistical functions. However, for most medium-difficulty questions, it is faster to use the "Sum = Average Γ— Number of Items" formula manually than to input data lists into a calculator.

    What is a "bimodal" data set?

    A bimodal data set is one that has two modes, meaning two different values appear with the same highest frequency. If a question asks for "the" mode of such a set, you would list both values, though the ACT typically avoids this ambiguity or asks for the sum of the modes.

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