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    Hard GRE Data Analysis Questions Practice Questions

    July 8, 202610 min read18 views
    Hard GRE Data Analysis Questions Practice Questions

    Approximately 25% of the GRE Quantitative Reasoning section focuses on data analysis, requiring deep proficiency in statistics, probability, and data interpretation. Hard GRE Data Analysis Questions test your ability to synthesize information from multiple charts, calculate complex probabilities, and apply advanced statistical concepts like standard deviation and normal distributions under time pressure. Success on these high-level problems often distinguishes top-tier scorers from the rest of the pack.

    To excel, students must move beyond basic mean and median calculations. The GRE Prep journey involves mastering the nuances of weighted averages, conditional probability, and the properties of bell curves. By engaging with Free GRE Practice Questions, you can begin to identify the logical traps the test-makers set, particularly in "Data Interpretation Sets" where one misread legend can lead to multiple incorrect answers.

    Concept Explanation

    Data Analysis on the GRE encompasses the collection, organization, analysis, interpretation, and presentation of data through statistical methods and probability theories. At the "Hard" difficulty level, these questions transition from simple retrieval to multi-step synthesis. You will frequently encounter scenarios involving the Normal Distribution, where you must apply the 68-95-99.7 rule to find percentiles, or Combinatorics, where the distinction between permutations and combinations is critical for counting outcomes.

    Advanced data interpretation often utilizes complex visuals such as box plots, scatterplots with lines of best fit, and dual-axis graphs. According to the Educational Testing Service (ETS), the focus is on your ability to model real-world scenarios mathematically. Key areas of focus include:

    • Descriptive Statistics: Understanding how adding or removing data points affects the standard deviation and interquartile range.
    • Probability: Calculating the likelihood of independent and dependent events, often using the complement rule: P ( A ) = 1 βˆ’ P ( not  A ) P(A) = 1 - P( \text{not } A) .
    • Data Interpretation: Analyzing percentage changes over time across different categories in a single table.

    Solved Examples

    1. Standard Deviation Shift
    A set of 100 test scores has a mean of 75 and a standard deviation of 8. If every score is increased by 5 points and then multiplied by 1.2, what is the new standard deviation?

    1. Recall that adding a constant to every value in a set changes the mean but has no effect on the standard deviation. After adding 5, the standard deviation remains 8.
    2. Recall that multiplying every value in a set by a constant k k multiplies the standard deviation by ∣ k ∣ |k| .
    3. Multiply the current standard deviation by 1.2: 8 Γ— 1.2 = 9.6 8 \times 1.2 = 9.6 .
    4. The new standard deviation is 9.6.

    2. Probability of "At Least One"
    A bag contains 4 red marbles and 6 blue marbles. If 3 marbles are drawn at random without replacement, what is the probability that at least one red marble is drawn?

    1. Use the complement rule: P ( at least 1 red ) = 1 βˆ’ P ( no red ) P( \text{at least 1 red}) = 1 - P( \text{no red}) .
    2. Calculate the probability of drawing 3 blue marbles in a row: 6 10 Γ— 5 9 Γ— 4 8 \frac{6}{10} \times \frac{5}{9} \times \frac{4}{8} .
    3. Simplify the fractions: 3 5 Γ— 5 9 Γ— 1 2 = 15 90 = 1 6 \frac{3}{5} \times \frac{5}{9} \times \frac{1}{2} = \frac{15}{90} = \frac{1}{6} .
    4. Subtract from 1: 1 βˆ’ 1 6 = 5 6 1 - \frac{1}{6} = \frac{5}{6} .

    3. Combinatorics in Committees
    A research department has 5 biologists and 4 chemists. How many different committees of 4 people can be formed if the committee must include at least 2 biologists?

    1. Identify the possible scenarios: (2B and 2C), (3B and 1C), or (4B and 0C).
    2. Calculate 2B and 2C: ( 5 2 ) Γ— ( 4 2 ) = 10 Γ— 6 = 60 \binom{5}{2} \times \binom{4}{2} = 10 \times 6 = 60 .
    3. Calculate 3B and 1C: ( 5 3 ) Γ— ( 4 1 ) = 10 Γ— 4 = 40 \binom{5}{3} \times \binom{4}{1} = 10 \times 4 = 40 .
    4. Calculate 4B and 0C: ( 5 4 ) Γ— ( 4 0 ) = 5 Γ— 1 = 5 \binom{5}{4} \times \binom{4}{0} = 5 \times 1 = 5 .
    5. Sum the scenarios: 60 + 40 + 5 = 105 60 + 40 + 5 = 105 .

    Practice Questions

    1. In a normal distribution with a mean of 50 and a standard deviation of 10, what is the approximate probability that a randomly selected value is between 30 and 60?

    2. A set S S consists of 7 distinct integers. If the median of S S is 15 and the range is 20, what is the maximum possible value for the largest integer in the set? (Assume all integers are positive).

    3. A box contains 10 light bulbs, of which 3 are defective. if 2 bulbs are chosen at random without replacement, what is the probability that both bulbs are non-defective?

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    4. The average (arithmetic mean) of 5 numbers is 20. If a 6th number is added, the new average is 22. What is the value of the 6th number?

    5. A data set has a mean of 10 and a standard deviation of 3. If every number in the set is multiplied by -2 and then 4 is added to the result, what is the new standard deviation?

    6. How many ways can the letters in the word "LEVEL" be rearranged?

    7. In a group of 60 students, 30 study Spanish, 20 study French, and 10 study both. How many students study neither Spanish nor French?

    8. A scatterplot shows a strong negative correlation between the number of hours spent watching TV ( x x ) and the score on a math test ( y y ). If the line of best fit is y = βˆ’ 5 x + 95 y = -5x + 95 what is the predicted score for a student who watches 4 hours of TV?

    Answers & Explanations

    1. Answer: 0.815 (or 81.5%)
    In a normal distribution, the range 30 to 60 covers two standard deviations below the mean (30) to one standard deviation above the mean (60). The area from -2 to 0 standard deviations is roughly 47.5%, and from 0 to +1 is 34%. Summing these gives 47.5 % + 34 % = 81.5 % 47.5\% + 34\% = 81.5\% .

    2. Answer: 31
    Let the set be { x 1 , x 2 , x 3 , 15 , x 5 , x 6 , x 7 } \{x_1, x_2, x_3, 15, x_5, x_6, x_7\} . To maximize x 7 x_7 , we must minimize x 1 x_1 . Since they are distinct positive integers, the smallest x 1 x_1 can be is 1. Since the range is 20, x 7 βˆ’ x 1 = 20 x_7 - x_1 = 20 . Thus, x 7 βˆ’ 1 = 20 x_7 - 1 = 20 , so x 7 = 21 x_7 = 21 . Correction: To maximize the largest value given the median, we check if the median constrains the range. If the median is 15, the smallest values could be 1, 2, 3. The largest value x 7 x_7 is simply x 1 + 20 x_1 + 20 . With x 1 = 11 x_1 = 11 , x 7 = 31 x_7 = 31 . If x 1 = 1 x_1 = 1 , x 7 = 21 x_7 = 21 . The constraint is distinct integers; 11, 12, 13, 15, 16, 17, 31 works. Thus, 31 is the maximum.

    3. Answer: 7/15
    There are 7 non-defective bulbs. The probability that the first is non-defective is 7 / 10 7/10 . The probability that the second is non-defective is 6 / 9 6/9 . Multiply them: 7 10 Γ— 6 9 = 42 90 = 7 15 \frac{7}{10} \times \frac{6}{9} = \frac{42}{90} = \frac{7}{15}

    4. Answer: 32
    Sum of 5 numbers = 5 Γ— 20 = 100 5 \times 20 = 100 . Sum of 6 numbers = 6 Γ— 22 = 132 6 \times 22 = 132 . The 6th number is 132 βˆ’ 100 = 32 132 - 100 = 32 .

    5. Answer: 6
    Addition does not affect standard deviation. Multiplication by -2 scales the standard deviation by the absolute value, ∣ βˆ’ 2 ∣ = 2 |-2| = 2 . Original SD 3 multiplied by 2 equals 6. You can practice similar transformations using an AI Question Generator.

    6. Answer: 30
    The word "LEVEL" has 5 letters with 'L' appearing twice and 'E' appearing twice. The formula is 5 ! 2 ! 2 ! = 120 4 = 30 \frac{5!}{2!2!} = \frac{120}{4} = 30

    7. Answer: 20
    Using the formula for the union of two sets: ∣ S βˆͺ F ∣ = ∣ S ∣ + ∣ F ∣ βˆ’ ∣ S ∩ F ∣ = 30 + 20 βˆ’ 10 = 40 |S \cup F| = |S| + |F| - |S \cap F| = 30 + 20 - 10 = 40 . The number of students studying neither is the total minus those studying at least one: 60 βˆ’ 40 = 20 60 - 40 = 20 .

    8. Answer: 75
    Substitute x = 4 x = 4 into the regression equation: y = βˆ’ 5 ( 4 ) + 95 = βˆ’ 20 + 95 = 75 y = -5(4) + 95 = -20 + 95 = 75

    Interactive quizQuestion 1 of 5

    1. If a data set has a variance of 16, what is its standard deviation?

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    Frequently Asked Questions

    What is the difference between a permutation and a combination on the GRE?

    A permutation is used when the order of selection matters, such as assigning specific seats, while a combination is used when the order does not matter, such as choosing a group of friends for a trip.

    How do I identify a normal distribution question?

    Look for keywords like "normally distributed," "bell-shaped curve," or mentions of standard deviations relative to the mean to apply the 68-95-99.7 rule. You can refine your timing for these questions using an AI Exam Simulator.

    Can the standard deviation of a set be negative?

    No, standard deviation is always zero or positive because it is the square root of the variance, which is based on squared distances from the mean.

    What is a "weighted average" on the GRE?

    A weighted average occurs when different data points contribute differently to the final average, usually requiring you to multiply each value by its frequency or weight before dividing by the total weight.

    How should I approach Data Interpretation sets with multiple graphs?

    Always read the titles, axes, and legends first to understand what each graph represents before reading the questions to avoid confusing different units or categories. For more targeted practice, check out GRE Reading Passage Questions which often share similar logical structures.

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