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    Hard ACT Percentage Practice Questions

    June 7, 202610 min read63 views
    Hard ACT Percentage Practice Questions

    Mastering Hard ACT Percentage Practice Questions is essential for students aiming for a top-tier score on the math section of the ACT, as these problems often combine multiple steps, algebraic variables, and multi-layered increases or decreases. While basic percentages require simple multiplication, the most challenging questions on the exam test your ability to handle compound changes and reverse calculations under time pressure.

    Concept Explanation

    Percentage problems on the ACT involve finding a part of a whole, calculating percent change, or determining an original value after a series of increases and decreases. At its core, a percentage is simply a ratio with a denominator of 100, expressed by the formula Part = Percent 100 Γ— Whole \text{Part} = \frac{ \text{Percent}}{100} \times \text{Whole} . To solve advanced problems, you must be comfortable converting percentages to decimals (e.g., 15% becomes 0.15) and using the percent change formula: Percent Change = New βˆ’ Original Original Γ— 100 \text{Percent Change} = \frac{ \text{New} - \text{Original}}{ \text{Original}} \times 100 .

    Harder variations often include "percent of a percent" scenarios or variables. For instance, if a price increases by 20% and then decreases by 20%, the final price is not the original price; it is actually 96% of the original ( 1.20 Γ— 0.80 = 0.96 1.20 \times 0.80 = 0.96 ). Understanding this multiplicative nature is a key strategy found in comprehensive ACT Prep resources. You should also be prepared for ACT Word Problems Practice Questions where percentages are embedded in complex narratives or real-world financial contexts like interest rates or tax calculations.

    Solved Examples

    1. Example 1: Compound Percentage Change
      A laptop's price is reduced by 30% for a holiday sale. After the sale, the discounted price is increased by 20%. What is the total percentage change from the original price to the final price?
      1. Let the original price be x x .
      2. After a 30% reduction, the price is 0.70 x 0.70x .
      3. Increasing this new price by 20% means multiplying by 1.20: 0.70 x Γ— 1.20 = 0.84 x 0.70x \times 1.20 = 0.84x .
      4. The final price is 84% of the original. The total change is 100 % βˆ’ 84 % = 16 % 100\% - 84\% = 16\% decrease.
    2. Example 2: Working Backwards
      After a 15% service tip and a 6% sales tax are added to the subtotal of a meal, the final bill is $54.81. If the tax is applied only to the subtotal (not including the tip), what was the original subtotal?
      1. Let the subtotal be S S .
      2. The tip is 0.15 S 0.15S and the tax is 0.06 S 0.06S .
      3. The equation is S + 0.15 S + 0.06 S = 54.81 S + 0.15S + 0.06S = 54.81 , which simplifies to 1.21 S = 54.81 1.21S = 54.81 .
      4. Divide by 1.21: S = 54.81 1.21 = 45.30 S = \frac{54.81}{1.21} = 45.30 . The subtotal was $45.30.
    3. Example 3: Percentages with Variables
      If y y is 150% of z z , and z z is 40% of w w , what percent of w w is y y ?
      1. Write the equations based on the descriptions: y = 1.5 z y = 1.5z and z = 0.4 w z = 0.4w .
      2. Substitute the expression for z z into the first equation: y = 1.5 ( 0.4 w ) y = 1.5(0.4w) .
      3. Calculate the product: 1.5 Γ— 0.4 = 0.6 1.5 \times 0.4 = 0.6 .
      4. Since y = 0.6 w y = 0.6w , y y is 60% of w w .

    Practice Questions

    Test your skills with these Hard ACT Percentage Practice Questions. These are designed to mimic the difficulty found in the final 20 questions of the ACT Math section. For more foundational work, you might visit Khan Academy's percentage lessons.

    1. A store owner increases the price of a jacket by 25%. After a month, the jacket hasn't sold, so she decreases the new price by 40%. The final sale price is $75. What was the original price of the jacket?
    2. In a certain school, 60% of students are female. If 20% of the female students and 30% of the male students are in the band, what percentage of the total student body is in the band?
    3. The population of Town A increased by 10% each year for two consecutive years. If the population at the end of the second year was 12,100, what was the population at the beginning of the first year?

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    1. If x x is 20% greater than y y , and y y is 20% less than z z , what is the ratio of x x to z z ?
    2. A solution is 20% salt by weight. If 50 grams of water are evaporated from 250 grams of the solution, what is the new percentage of salt in the solution?
    3. A manufacturer produces 2,000 units of a product. 5% are found to be defective. Of the remaining non-defective units, 10% are sent back for minor repairs. How many units were neither defective nor sent back for repairs?
    4. If the radius of a circle increases by 50%, by what percentage does the area of the circle increase?
    5. A real estate agent receives a 3% commission on the first $200,000 of a sale and 2% on any amount over $200,000. If the agent received a total commission of $8,400, what was the sale price of the house?
    6. In a container, there are red, blue, and green marbles. 30% are red. Of the remaining marbles, 40% are blue. If there are 42 green marbles, how many total marbles are in the container?
    7. A stock price drops by 20% on Monday. By what percentage must it increase on Tuesday to return to its original price from Monday morning?

    Answers & Explanations

    1. Answer: $100
      Let the original price be P P . After a 25% increase, the price is 1.25 P 1.25P . After a 40% decrease on that new price, the price is 0.60 ( 1.25 P ) = 0.75 P 0.60(1.25P) = 0.75P . Setting this equal to the final price: 0.75 P = 75 0.75P = 75 . Dividing by 0.75 gives P = 100 P = 100 .
    2. Answer: 24%
      Assume there are 100 students. 60 are female and 40 are male. In the band, there are 0.20 ( 60 ) = 12 0.20(60) = 12 females and 0.30 ( 40 ) = 12 0.30(40) = 12 males. Total band members = 12 + 12 = 24 12 + 12 = 24 . Out of 100 students, this is 24%.
    3. Answer: 10,000
      Let the starting population be P P . After one year: 1.10 P 1.10P . After two years: 1.10 ( 1.10 P ) = 1.21 P 1.10(1.10P) = 1.21P . Set 1.21 P = 12 , 100 1.21P = 12,100 . Solving for P P gives P = 10 , 000 P = 10,000 .
    4. Answer: 24:25
      We have x = 1.2 y x = 1.2y and y = 0.8 z y = 0.8z . Substitute y y into the first equation: x = 1.2 ( 0.8 z ) = 0.96 z x = 1.2(0.8z) = 0.96z . The ratio x z = 0.96 = 96 100 = 24 25 \frac{x}{z} = 0.96 = \frac{96}{100} = \frac{24}{25} .
    5. Answer: 25%
      Original salt weight = 0.20 Γ— 250 = 50 0.20 \times 250 = 50 grams. After 50g of water evaporates, the total weight is 250 βˆ’ 50 = 200 250 - 50 = 200 grams. The salt weight remains 50g. New percentage = 50 200 Γ— 100 = 25 % \frac{50}{200} \times 100 = 25\% .
    6. Answer: 1,710
      Defective units = 0.05 Γ— 2 , 000 = 100 0.05 \times 2,000 = 100 . Non-defective = 1 , 900 1,900 . Units sent for repair = 0.10 Γ— 1 , 900 = 190 0.10 \times 1,900 = 190 . Units neither defective nor repaired = 1 , 900 βˆ’ 190 = 1 , 710 1,900 - 190 = 1,710 .
    7. Answer: 125%
      Area A = Ο€ r 2 A = \pi r^2 . If r r becomes 1.5 r 1.5r , the new area is Ο€ ( 1.5 r ) 2 = 2.25 Ο€ r 2 \pi(1.5r)^2 = 2.25 \pi r^2 . The increase is 2.25 βˆ’ 1 = 1.25 2.25 - 1 = 1.25 , which is 125%.
    8. Answer: $320,000
      Commission on first $200,000 = 0.03 Γ— 200 , 000 = 6 , 000 0.03 \times 200,000 = 6,000 . Remaining commission = 8 , 400 βˆ’ 6 , 000 = 2 , 400 8,400 - 6,000 = 2,400 . Let x x be the amount over $200,000. 0.02 x = 2 , 400 β‡’ x = 120 , 000 0.02x = 2,400 \Rightarrow x = 120,000 . Total price = 200 , 000 + 120 , 000 = 320 , 000 200,000 + 120,000 = 320,000 .
    9. Answer: 100
      Let total be T T . Red = 0.3 T 0.3T . Remaining = 0.7 T 0.7T . Blue = 0.4 ( 0.7 T ) = 0.28 T 0.4(0.7T) = 0.28T . Green = T βˆ’ 0.3 T βˆ’ 0.28 T = 0.42 T T - 0.3T - 0.28T = 0.42T . Set 0.42 T = 42 0.42T = 42 . Solving for T T gives 100.
    10. Answer: 25%
      If the price starts at $100, it drops to $80. To get back to $100, it must increase by $20. 20 80 = 0.25 \frac{20}{80} = 0.25 , or 25%.

    For more practice with algebraic relationships, check out our guide on ACT Ratio Practice Questions. To further sharpen your skills, using the AI Question Generator can provide an endless supply of problems tailored to your specific weak points.

    Interactive quizQuestion 1 of 5

    1. If a quantity increases by 100%, it is equivalent to multiplying the original quantity by:

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    Frequently Asked Questions

    How do I handle multiple percentage changes in a row?

    You must treat each change sequentially by multiplying the decimal equivalents of the changes. For example, a 10% increase followed by a 10% decrease is calculated as 1.10 Γ— 0.90 = 0.99 1.10 \times 0.90 = 0.99 , representing a 1% total decrease.

    What is the most common mistake on ACT percentage questions?

    The most common error is adding or subtracting percentages directly (e.g., assuming a 20% increase and a 20% decrease cancel out) rather than applying them as multipliers. Always remember that the second percentage is applied to the new value, not the original one.

    How do I convert a percentage to a decimal quickly?

    Move the decimal point two places to the left and remove the percent sign. For example, 7% becomes 0.07, and 125% becomes 1.25, which is a crucial step for setting up equations in ACT Algebra Practice Questions.

    Are calculators allowed for percentage problems on the ACT?

    Yes, calculators are permitted on the ACT Math section, and they are highly recommended for percentage problems to avoid arithmetic errors. For official guidelines on acceptable models, refer to the ACT Calculator Policy.

    What is the difference between "percent of" and "percent more than"?

    "Percent of" refers to the direct fraction (e.g., 20% of 80 is 0.20 Γ— 80 = 16 0.20 \times 80 = 16 ), while "percent more than" implies adding that amount to the original (e.g., 20% more than 80 is 80 + 16 = 96 80 + 16 = 96 ).

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